Dik : g = 4,1 gram
Mr = 82
Ka = 10⁻⁵
V = 1L
M = g/Mr.V
= 4,1/(82.1 L)
= 0,05 M
Dit : pH = ......?
Jwb : [OH⁻] = √Kw.M/Ka
= √ 10⁻¹⁴.50.10⁻³/10⁻⁵
= √50 x 10⁻⁶ M
pOH = - log √50 x 10⁻⁶ = 6 - log √50 = 6 - 0,85 = 5,15
Dik : g = 4,1 gram
Mr = 82
Ka = 10⁻⁵
V = 1L
M = g/Mr.V
= 4,1/(82.1 L)
= 0,05 M
Dit : pH = ......?
Jwb : [OH⁻] = √Kw.M/Ka
= √ 10⁻¹⁴.50.10⁻³/10⁻⁵
= √50 x 10⁻⁶ M
pOH = - log √50 x 10⁻⁶ = 6 - log √50 = 6 - 0,85 = 5,15