Dalam segitiga diatas panjang ab = 8cm, ac = 6cm, bc = 10cm. Hitunglah panjang AD

AD² = 8² - BD²
AD² = 6² - CD²
8² - BD² = 6² - CD²
28 - BD² = -CD²
28 = BD² - CD²
28 = (BD + CD)(BD-CD)
BD - CD = 2,8
BD + CD = 10
BD - CD = 2,8 _
2CD  = 7,2
CD = 3,6
AD = √(36 - (3,6)²)
= √(36 - 12,96) = √(23,04) = 4,8
AD = 4,8 CM

Source https://sebuahcatatan.live/as/catatanbrain/tugas/2171553